1.

In the given circuit, what is the value of IC if the BJT is made of Silicon?(a) 2.01 mA(b) 2.01 uA(c) 10.05 mA(d) 10.05 uAI got this question in an internship interview.The doubt is from BJT DC biasing in division BJT Biasing of Analog Circuits

Answer»

The CORRECT ANSWER is (a) 2.01 mA

To EXPLAIN: Consider the BJT to be in SATURATION. Then IC=20-0.2/2k=9.9 mA

And IB=20-0.8/430k=0.044 mA

IBMIN=ICSAT/β=5.09/50=0.198mA which is greater than above IB.

Hence transistor is in the ACTIVE region.

Thus IC=βIB.

VBE=0.7V

IB=20-0.7/430=44.88μA

IC=50×44.88=2.24 mA.



Discussion

No Comment Found

Related InterviewSolutions