1.

In the given circuit , when key K is open, reading of ammeter is I. Now key K is closed, then the correct statement is

Answer»

If `epsilon_1 lt IR`, reading OG the ammeter is less than I.
If `IR GT epsilon_1`, reading of the ammeter is greater than I.
If `epsilon_1gt 2IR`, reading og the ammeter will be ZERO.
Reading of ammeter will not CHANGE.

Solution :b. `R(i_1 + i_2) = E_1`
`i_2R + (i_1 + i_2) R = E_2`
`i_2 = (E_2 - E_1)/R `
[Initially, `E = E_2//R`].


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