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In the given circuit, with steady current, the potential drop across the capacitor must be |
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Answer» SOLUTION :Apply Kirchhoff.s law to the closed mesh ACDFA, `2V-I(2R)-I(R )-V=0` or `V=3IR or I=(V )/(3R )` APPLYING Kirchhoff.s law of the mesh ABEFA, `V+V_(C )-IR-V=0` or `V_(C )=IR=((V)/(3R))R=(V)/(3)` `THEREFORE"Potential difference across capacitor "V_(C )=(V )/(3)` |
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