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In the given elliptical `P-V` diagram A. the work done is positiveB. the change in internal energy is non-zeroC. the work done ` = - (pi//4) (P_(2) - P_(1)) (V_(2) - V_(1))`D. the work done `= pi (V_(1) - V_(2))^(2) - pi (P_(1) - P_(2))^(2)` |
Answer» Correct Answer - C c. The work done = area of `P - V` diagram `a = (V_(2) - V_(1))/(2), b = (P_(2) - P_(1))/(2)` `W = - pi ((V_(2) - V_(1))/(2)) ((P_(2) - P_(1))/(2))` But the cyclic process is anitclockwise, Hence, the wor done is negative |
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