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In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that∠AED = 138° and ∠BAE = 75°. Find ∠ECD. |
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Answer» -STEP EXPLANATION:ANGLE BAE = angle EDC = 75° [ angles in the same segment BC are EQUAL ] angle AED + angle DEC = 180° [ Linear pair]angle DEC = 180° - 138° = 42°In triangle EDC,angle DEC + angle EDC + angle ECD = 180°[ angle sum property of a triangle ] angle ECD = 63° |
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