1.

In the given figure, a wire loop has been bent so that it has three segments. Portion OABO is quarter circle in xy plane, portion OBC is a right angle triangle in xz plane and portion OCDAO is a square in yz plane. Here are three choices for a magnetic field through the loop. (1) vecB_(1)=3hati+7hatj-5thatk (2) vecV_(2)=5thati-4hatj-15hatk (3) vecB_(3)=2hati-5thatj-12hatk If the induced current in the loop due to vecB_(1), vecB_(2) and vecB_(3) are i_(1), i_(2) and i_(3) respectively then :

Answer»

`i_(1) lt i_(2)`
`i_(1) gt i_(2)`
`i_(3) gt i_(2) gt i_(1)`
`i_(1) = i_(2) = i_(3)`

Solution :At any TIME `t`,
`OMEGA=(U sin60^(@))/(x)`
`alpha=(u sin 60^(@))/(x^(2))(-(dx)/(dt))`
`alpha=(usin60^(@))/(x^(2))(u+ucos60^(@))`
`alpha` at `t=0`
`alpha=(usin60^(@))/(a^(2))(u+ucos60^(@))=9rad//s^(2)`


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