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In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to(a) ΔEFC(b) ΔECF(c) ΔCEF(d) ΔFEC |
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Answer» In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to (a) ΔEFC (b) ΔECF (c) ΔCEF (d) ΔFEC
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