1.

In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to(a) ΔEFC(b) ΔECF(c) ΔCEF(d) ΔFEC

Answer» In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to



(a) ΔEFC



(b) ΔECF



(c) ΔCEF



(d) ΔFEC




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