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In the given figure, AB || CD and XY is a transversal line intersects AB and CD at E and G respectively. If EF and GF are the bisectors of ∠BEG and ∠DGE respectively, then the measure of ∠EFG is equal to |
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Answer» let BEF= aas AB //CDSoDfe = 180 - aEG is bisector of BEFSo FEG = a / 2 ,And FG is bisector of DFESo GFE=180-a)/2=90-a/2In FGEFGE= 180 - FEG - GFE= 180-a/290 + a/2= 90Step-by-step explanation:HOPE it helps you |
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