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In the given figure, AB is a chord of a circle with centre O and AB is produced to C such that BC = OB. Also, CO is joined and produced to meet the circle in D. If ∠ACD = 25°, then ∠AOD =? |
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Answer» , OB = BC⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal]∠OBA is the EXTERIOR angle of △BOCSo, ∠ABO = 2Y ...[ext. angle is equal to the SUM of INT. opp. angles]Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y |
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