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| 1. |
In the given figure, ABC is a triangle in which AB = AC and D is a point on AC. Through C, a line is drawn to intersect BD produced at E, such that ∠ABE = ∠ACE. Prove that ∠AEC = 90° + 1/2 ∠BAC |
| Answer» LOOK ABC KA ANSWER is too EASY | |