1.

In the given figure ABCD is a parallelogram. ABEF is a rectangle. Show that ΔAFD ≅ ΔBEC

Answer»

Given that □ABCD is a parallelogram. 

□ABEF is a rectangle. 

In ΔAFD and ΔBEC 

AF = BE ( ∵ opp. sides of rectangle □ABEF) 

AD = BC (∵ opp. sides of //gm □ABCD) 

DF = CE (∵ AB = DC = DE + EC , AB = EF = DE + DF) 

∴ ΔAFD ≅ ΔBEC (SSS congruence)



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