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In the given figure ABCD is a parallelogram. ABEF is a rectangle. Show that ΔAFD ≅ ΔBEC |
Answer» Given that □ABCD is a parallelogram. □ABEF is a rectangle. In ΔAFD and ΔBEC AF = BE ( ∵ opp. sides of rectangle □ABEF) AD = BC (∵ opp. sides of //gm □ABCD) DF = CE (∵ AB = DC = DE + EC , AB = EF = DE + DF) ∴ ΔAFD ≅ ΔBEC (SSS congruence) |
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