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In the given figure, ABCD is a rectangle of 20 cm x 10 cm. A semicircle is drawn with centre O, radius `10sqrt2` cm and it passes through A and B. Find the area of the shaded region. [Use `pi=22/7`] |
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Answer» Area of APB=Area of sector OAPB-Area of `/_OAB` `=90/360*pi(10sqrt2)^2-1/2*20*10` Area of Area APB=400/7 Area of shaded region= Area of rectangle ABCD- Area of triangle APB `20*10-400/7` `(1400-400)/7` `1000/7 cm^2`. |
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