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In the given figure, ABCD is the cyclic quadrilateral in which BC = CD and ∠CBD = 35°. Then, ∠BAD = ? |
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Answer» D ,CBD = CDB [as,CB=CD]= 35°FIRST METHOD :Using Angle Sum PropertyCBD+CDB+BCD = 180°35° + 35° +BCD = 180°BCD + 70° = 180° BCD = 110°NOW, BCD + BAD=180°because , it's a cyclic Quadrilateral..so, BAD= 70°SECOND METHOD :ABC= ADC= 90° [ Angle in SEMICIRCLE ]ABD + DBC = ABCABD + 35° = 90°ABD = 55°Similarly, ADB = 55°Now , in ∆ABDusing Angle Sum PROPERTY,ABD+ADB+BAD= 180°55° + 55° + BAD = 180°BAD + 110° = 180°BAD= 70° |
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