In the given figure , ABCD isa rhombus .Diagonals AC and BD intersect

1.	In the given figure , ABCD isa rhombus .Diagonals AC and BD intersect at O .
Answer» Answer: angle OAB =55° angle DAB = 552=110° [diagonals of RHOMBUS bisect the VERTEX angles] angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram] angle ABC = 180- angle DAB= 180-110=70° Angle ADC= angle ABC =70° Step-by-step EXPLANATION:*

In the given figure , ABCD isa rhombus .Diagonals AC and BD intersect at O .

Answer»

Answer:

angle OAB =55°

angle DAB = 55*2=110° [diagonals of RHOMBUS bisect the VERTEX angles]

angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]

angle ABC = 180- angle DAB= 180-110=70°

Angle ADC= angle ABC =70°

Step-by-step EXPLANATION: