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In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC =? |
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Answer» ⇒ In △ABC,⇒ ∠BCA=90 o [ Angle INSCRIBED in semi-circle ]⇒ AC=BC [ GIVEN ]∴ ∠ABC=∠CAB [ Opposite angles of EQUAL SIDES are equal ]∴ ∠CAB+∠ABC+∠BCA=180 o ∴ ∠CAB+∠CAB=90 o =180 o ∴ 2∠CAB=180 o −90 o ∴ 2∠CAB=90 o ∴ ∠CAB=45 o |
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