In the given figure, ΔQPS = ΔSRQ. Find each value.(a) x(b) ∠PQS(c)

1.	In the given figure, ΔQPS = ΔSRQ. Find each value.(a) x(b) ∠PQS(c) ∠PSRthe fastest is brainliest
Answer» Answer: Angle R = 106° (opposite angle of \|\|gram are EQUAL) 106° = 2x + 12 106° - 12 = 2x 94° = 2x x = 94/2 x = 47° ______________________________________ Let angle S be y. We KNOW that sum of interior ANGLES of a ∆ = 180° then, 106° + 42° + y = 180° 148° + y = 180° y = 180° - 148° y = 32° PLEASE MARK AS BRAINLIEST AND ALSO FOLLOW ME ☺️✌

In the given figure, ΔQPS = ΔSRQ. Find each value.(a) x(b) ∠PQS(c) ∠PSRthe fastest is brainliest

Answer»

Answer:

Angle R = 106° (opposite angle of ||gram are EQUAL)

106° = 2x + 12

106° - 12 = 2x

94° = 2x

x = 94/2

x = 47°

______________________________________

Let angle S be y.

We KNOW that sum of interior ANGLES of a ∆ = 180°

then,

106° + 42° + y = 180°

148° + y = 180°

y = 180° - 148°

y = 32°