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.In the given figure, find PM (a) 3 cm (b) 5 cm (c) 4 cm (d) 2 cm |
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Answer» Answer: In the given figure ∠LOP = ∠MOP , OL = 3cm , OP = 5cm , ∠PLO = ∠PMO [ as right angles ] Firstly we have to prove that traingle LOP is congruent to traingle mop se we will PROOF the congruence of those traingle s In traingle LOP and traingle MOP ∠LOP = ∠MOP OP = OP [common] ∠PLO = ∠PMO [ right angles ] Hence , ΔLOP ≅ΔMOP PM = PL [ by CPCT ] So , here we have got to know that PL = PM so if we find tHe value of PL it will be equal to PM So , we can find the value of PL by the pythagoras theorem that is to be APPLIED in ΔPLO , OP²= LP²+OL² [5]²= [3]²+LP² 25= 9 +LP² LP²= 25- 9 LP= √16 = 4cm As we know that PM= PL So , PL = PM = 4cm OPTION [C] THANK U !! HOPE IT DOES HELP U !! IF SO PLZ MRK THE BRAINLIEST !!! |
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