1.

In the given figure,if ABCD is a rectangle in which angle APB =100° ,then find the value of x. ​

Answer»

50Step-by-step explanation:P=100(VERTICALLY opposite ANGLE. Y=180-100=80. 100+x+x=1802x=180-100=80. 80 DIVIDED by 2x=40A=40 B=40 F=90-40=50Y+F+X=18080+50+X=180X=180-130X=50



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