1.

In the given figure, O is the centre of the circle and AB is the diameter of the circle. If difference of ∠COD and ∠DBC is 25°, then find the measure of ∠DEB. Please solve this question, I need it urgently. ​

Answer»

O is the CENTRE of the circle and AB is the diameter of the circle.  difference of ∠COD and ∠DBC is 25° To Find : the measure of ∠DEB.Solution:∠COD = 2∠DBC   ANGLE be same ARC CD at center and remaining circle  ∠COD = ∠DBC + 25°=>  2∠DBC  = ∠DBC + 25°=> ∠DBC  = 25°∠ADB = 90°   as AB is diameter   ∠CDB = 180° - ∠ADB   ( linear pair)=> ∠CDB =90° ∠DBC + ∠CDB + ∠DEB. = 180°  ( sum of angles of TRIANGLE)=> 25° + 90° + ∠DEB. = 180°=>  ∠DEB. = 65°measure of ∠DEB.  = 65° Learn More:Ab is the diameter of a circle with centre o and cd is chord prove ... brainly.in/question/8079524a circle with center O, two chords AB and CD are drawn which ... brainly.in/question/21665219



Discussion

No Comment Found

Related InterviewSolutions