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In the given figure, O is the centre of the circle and AB is the diameter of the circle. If difference of ∠COD and ∠DBC is 25°, then find the measure of ∠DEB. Please solve this question, I need it urgently. |
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Answer» O is the CENTRE of the circle and AB is the diameter of the circle. difference of ∠COD and ∠DBC is 25° To Find : the measure of ∠DEB.Solution:∠COD = 2∠DBC ANGLE be same ARC CD at center and remaining circle ∠COD = ∠DBC + 25°=> 2∠DBC = ∠DBC + 25°=> ∠DBC = 25°∠ADB = 90° as AB is diameter ∠CDB = 180° - ∠ADB ( linear pair)=> ∠CDB =90° ∠DBC + ∠CDB + ∠DEB. = 180° ( sum of angles of TRIANGLE)=> 25° + 90° + ∠DEB. = 180°=> ∠DEB. = 65°measure of ∠DEB. = 65° Learn More:Ab is the diameter of a circle with centre o and cd is chord prove ... brainly.in/question/8079524a circle with center O, two chords AB and CD are drawn which ... brainly.in/question/21665219 |
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