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In the given figure , ^pQR=90°,QT perpendicular to PR, PQ=7cm,QR=24cm &PR=25cm then the length of TE is? |
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Answer» Given : In triangle PQR=90°,QT perpendicular to PR PQ=7cm,QR=24cm and PR=25cm To Find : the length of TR is Solution: 7² + 24² = 25² => PQ² + QR² = PR² Using Converse of PYTHAGORAS theorem PQR is right ANGLE triangle at Q and QT is Perpendicular ΔQTR ≈ Δ PQR => TR/QR = QR/PR => TR/24 24/25 => TR = 23.04 length of TR is 23.04 cm Learn More: using the concept of Pythagoras theorem construct a segment of ... draw a tangent segment of length √12 cm the CIRCLE with centre o ... |
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