in the given figure the perimeter of ABCDE is 16m find the smallest si

1.	in the given figure the perimeter of ABCDE is 16m find the smallest side CD . also find BE ,if the perimeter of ABE is 8m
Answer» Answer: Perimeter of the RECTANGLE = PQ + QR + RS + SP = b +l + b + l = 2B +2l Again, ABCD is a rectangle. We know that the opposite sides of a rectangle are equal. Perimeter of a Rectangle AB = CD = 5 cm and BC = AD = 3 cm So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm It can be written as 5 cm + 5 cm + 3 cm + 3 cm = (2 × 5) cm + (2 × 3) cm = 2 (5 + 3) cm = 2 × 8 cm = 16 cm We add length and BREADTH twice to find the perimeter of a rectangle. Perimeter of a rectangle = 2 (length + breadth)

in the given figure the perimeter of ABCDE is 16m find the smallest side CD . also find BE ,if the perimeter of ABE is 8m

Answer»

Answer:

Perimeter of the RECTANGLE = PQ + QR + RS + SP

= b +l + b + l

= 2B +2l

Again,

ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.

Perimeter of a Rectangle

AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

= (2 × 5) cm + (2 × 3) cm

= 2 (5 + 3) cm

= 2 × 8 cm

= 16 cm

We add length and BREADTH twice to find the perimeter of a rectangle.

Perimeter of a rectangle = 2 (length + breadth)