In the given figure, the sides AB and AC of ∆ABC are produced to poi

1.	In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A
Answer» Step-by-step EXPLANATION: the RIGHT ANSWER is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the

In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A

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Step-by-step EXPLANATION:

the RIGHT ANSWER is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the answer is the

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In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A​

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In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A