In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A

In the given figure, the sides AB and AC of ∆ABC are produced to poi

1.	In the given figure, the sides AB and AC of ∆ABC are produced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCD respectively meet at point O, then prove that ∠BOC = 90°–12∠A
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