In the given figure, the sides AB and AC of ∆ABC areproduced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCDrespectively meet at point O, then prove that∠BOC = 90°– 1/2∠A

In the given figure, the sides AB and AC of ∆ABC areproduced to poin

1.	In the given figure, the sides AB and AC of ∆ABC areproduced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCDrespectively meet at point O, then prove that∠BOC = 90°– 1/2∠A
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In the given figure, the sides AB and AC of ∆ABC areproduced to points E and D respectively.If bisectors BO and CO of ∠CBE and ∠BCDrespectively meet at point O, then prove that∠BOC = 90°– 1/2∠A

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