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In the given figure, triangles ABC and DCB are right-angled at A and D respectively and AC = DB. Prove that ΔABC = ΔDCB. |
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Answer» Given, Triangles ABC and DCB are right-angled at A and D respectively. AC = DB To prove, ΔABC = ΔDCB Proof, In ΔABC and ΔDCB: AC = DB (given) BC = BC (common) ∠CAB = ∠BDC = 90o From the RHS congruence property, ΔABC ≅ ΔDCB. |
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