1.

In the given figure what is the magnetic field induction at point O?

Answer»

`(mu_(0)I)/(4pi r)`
`(mu_(0)I)/(4r) + (mu_(0)I)/(2pi r)`
`(mu_(0)I)/(4r) + (mu_(0)I)/(4pi r)`
`(mu_(0)I)/(4r) -(mu_(0)I)/(4pi r)`

SOLUTION :FIELD at O due to VERTICAL straight wire= ZERO. Field at O due to circular part `= (mu_(0)I)/(4r)` (upwards)
Field at O due to horizontal part `=(mu_(0)I)/(4pi r)` (upwards)
`:.` Net field at O, `B= (mu_(0)I)/(4r) + (mu_(0)I)/(4pi r)`


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