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In the given limiter circuit, an input voltage Vi=10sin100πt is applied. Assume that the diode drop is 0.7V when it’s forward biased. The zener breakdown voltage is 6.8V.The maximum and minimum values of outputs voltage are _______(a) 6.1V,-0.7V(b) 0.7V,-7.5V(c) 7.5V,-0.7V(d) 7.5V,-7.5VThis question was posed to me in a national level competition.This intriguing question comes from Breakdown Diodes in section Semiconductor-Diode Characteristics of Electronic Devices & Circuits

Answer»

The correct option is (c) 7.5V,-0.7V

The explanation is: With VI= 10V when MAXIMUM, D1 is FORWARD biased, D2 is reverse biased. ZENER is in breakdown REGION. VOMAX=sum of breakdown voltage and diodedrop=6.8+0.7=7.5V. VOMIN=negative of voltage drop=-0.7V. There will be no breakdown voltage here.



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