1.

In the lead-acid battery during charging, the cathode reaction is

Answer»

FORMATION of `PbO_(2)`
formation of `PbSO_(4)`
reduction of `PB^(2+)` to `Pb`
decomposition of Pb at the anode

Solution :During chargin, the reaction that occur are
At cathode:
`PbSO_(4)(s)+2e^(-)toPb(s)+SO_(4)^(2-)(aq)`
At anode: `PbSO_(4)(s)+2H_(2)OtoPbO_(2)(s)+SO_(4)^(2-)(aq)+4H^(+)(aq)+2e^(-)`
Thus, `Pb^(2+)` ions of `PbSO_(4)` are REDUCED to Pb on the cathode while `PbSO_(4)` is oxidized to `PbO_(2)` at anode.
(Remember: Anode is the electrode on which oxidation takes place, i.e., loss of electrons and cathode is the electrode on which reduction takes place i.e., gain of electrons further, the electrode which ACTS as anode during discharge acts as cathode durig CHARGING and vice-versa.


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