In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26G and the dip angle is 60^(@). What is the magnetic field of the earth at this location?

In the magnetic meridian of a certain place, the horizontal component

1.	In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26G and the dip angle is 60^(@). What is the magnetic field of the earth at this location?
Answer» Solution :It is given that `H_(E)=0.26G`. From Fig 5.11 we have `cos 60^@=(H_(E))/(B_(E))` `B_(E)=(H_(E))/(cos 60^(@))` `=(0.26)/((1//2))=0.52 G`

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In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26G and the dip angle is 60^(@). What is the magnetic field of the earth at this location?

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