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In the manufacture of sulphuric acid write : (i) The equation with condition for oxidation of SO_(2) to SO_(3). (ii) Formation of Oleum from SO_(3). |
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Answer» Solution :(i) `2SO_(2)(G) + O_(2) rarr 2SO_(3)` Any one conditions : Temperature = 270 K or Pressure = 2bars or Catalyst `= V_(2)O_(5)` (ii) `SO_(3) + H_(2)SO_(4) rarr H_(2)S_(2)O_(7)` (Oleum) (i) In manufacturing of `H_(2)SO_(4)`, equation with condition for oxidation of `SO_(2)` to `SO_(3)` are as follows : Equations : `2SO_(2) + O_(2) overset("catalyst")hArr 2SO_(3)`. Condition : (a) Oxidation is ALWAYS done by passing warm `SO_(2)` bearing gas, through a catalyst like , V, K, NA, Cs, `SIiO_(2)` etc. Now a days `V_(2)O_(5)` (Vanadium penta oxide) is perfered, as it is cheaper and not poisoned by impurities. (b) Low temperature (about 720 K). (c ) Excess of air. (d) High pressure (about 2 atm). (ii) Formation of Oleum from `SO_(3)` : `SO_(3) + H_(2)SO_(4) rarr underset("(Oleum)")(H_(2)S_(2)O_(7))` `SO_(3)` cannot absorbed in water because it produces dense fog, while `H_(2)SO_(4)` absorbs `SO_(3)` to GIVE oleum. |
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