In the nth stable orbit of a hydrogen atom, the energy of an electronE =-(13.6)/(n^(2)) eV. Theenergy required to take the electron from first orbit to second orbit will be

In the nth stable orbit of a hydrogen atom, the energy of an electronE

1.	In the nth stable orbit of a hydrogen atom, the energy of an electronE =-(13.6)/(n^(2)) eV. Theenergy required to take the electron from first orbit to second orbit will be
Answer» 10.2 EV 12.1 eV 13.6 eV 3.4 eV Solution :Energy required ` E = E_(2) - E_(1) =(-13.6)/((2)^(2)) - [-(13.6)/((1)^(2))] = - 3.4 + 13.6 =+ 10.2 eV`

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In the nth stable orbit of a hydrogen atom, the energy of an electronE =-(13.6)/(n^(2)) eV. Theenergy required to take the electron from first orbit to second orbit will be

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