In the nuclear reaction ._(12)Mg^(24) + ._(2)He^(4) = ._(0)n^(1) + ? T – InterviewSolution

1.	In the nuclear reaction ._(12)Mg^(24) + ._(2)He^(4) = ._(0)n^(1) + ? The product nucleus is
Answer» `._(13)Al^(27)` `._(14)Si^(27)` `._(13)Al^(28)` `._(12)Mg^(25)` Solution :`._(12)Mg^(24) + ._(2)He^(4) rarr ._(0)N^(1) + ._(14)Si^(27)`

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