1.

In the nuclear reaction ""_(3) Li^(7) + ""_(1) H^(1) to 2""_(2) He^(4) . The mass loss is nearly 0.02 amu . Hence the energy released in the process is x xx 10^(2) million kcal l mole . (nearly) . Then 'x' is ____

Answer»


SOLUTION :`Q = ((0.02 xx 931.5 xx 10^(6) xx 1 .602 xx 10^(-19) xx 6 xx 10^(23))/(4 .18 xx 1000)) = 42.84 xx 10^(3+ 4)`
`= 4.284 xx 10^(8)` Kcal/mole = `4.28 xx (10^(8))/(10^(6))` million Kcal/mole = `4 xx 10^(2)` million Kcal/mole


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