1.

In the nuclear reaction ._(92)U^(238) rarr ._(82)Pb^(206), the number of alpha and beta particles decayed are

Answer»

`4 alpha, 3 beta`
`8 alpha, 6 beta`
`6 alpha, 4 beta`
`7 alpha, 5 beta`

SOLUTION :NUMBER of `alpha`- particles `= (238 - 206)/(4) = 8`
Number of `beta`- particles `= 2XX 8 - 92 + 82 = 6`


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