1.

In the nuclear transmutation ._(4)^(9)Be + X rarr ._(4)^(8)Be + Y (X, Y) is (are)

Answer»

<P>`(GAMMA, N)`
`(p, D)`
`(n, D)`
`(gamma, p)`

Solution :`._(4)Be^(9) + X rarr ._(4)Be^(8) + Y`
If X is `._(0)gamma^(0)` then Y is `._(0)n^(1)`
If X is `._(1)p^(1)` then Y is `._(1)D^(2)`


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