1.

In the oxidation of N_(2)H_(4) "to"N_2equivalent weight of N_(2)H_(4)would be........

Answer»


Solution :`overset(2xx2)(N_(2)H_4)rarroverset(2xx2)(N_(2))+4E^(-)`
EQUIVALENT weight = `{:(""GMW),(bar"change in oxidation "),("state for one"),("formula unit"):}=cancel(32)/cancel(4)=8, :. "EQ. wt of "N_(2)H_(4)=8``


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