1.

In the presence of a catalyst, the activation energy of a reaction is lowered by 2 kcal at 27^(@)C. The rate of reaction will increase by

Answer»

2 times
14 times
28 times
20 times

Solution :`k_1=Ae^(-(E_(a)-2)//RT)`
`k_2=Ae^(-(E_(a)-2)//RT)=Ae^(-E_(a)//RT_(E^(2//RT)))`
`:.""k_(2)/k_(1)=e^2//RT"orin"k_2/k_1=2/(RT)`
Putting `R=2xx10^(-3)`kcal `K^(-1) mol^(-1)`
and `T=300 K,`we get
`log""k_2/k_1=2/(2*303xx2xx10^-3xx300)=1*4473`
`:."" k_2/k_1=28"or"k_(2)=28xxk_1`


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