In the presence of excess base and excess halogen a methylketone is converted first into a trihalo substituted ketone and then into a carboxylic acid.After the trihalo substituted ketone is formed hydroxide ion attacks the carboxyl carbon because the trihalo methyl ion is the group more easily expelled from the tetrahedral intermediate.The conversion of a methyl ketone to a carboxylic acid is called a haloform reaction because one of the product is haloform (CHCl_3) or CHI_3 or CHBr_3. Which of the following compound show haloform reaction and racemisation in OD^(-) //D_2O

In the presence of excess base and excess halogen a methylketone is co

1.	In the presence of excess base and excess halogen a methylketone is converted first into a trihalo substituted ketone and then into a carboxylic acid.After the trihalo substituted ketone is formed hydroxide ion attacks the carboxyl carbon because the trihalo methyl ion is the group more easily expelled from the tetrahedral intermediate.The conversion of a methyl ketone to a carboxylic acid is called a haloform reaction because one of the product is haloform (CHCl_3) or CHI_3 or CHBr_3. Which of the following compound show haloform reaction and racemisation in OD^(-) //D_2O
Answer» `CH_3CH_2OH` `CH_3-undersetunderset(O)(\|\|)C-undersetunderset(Et)(\|)CH-PH` SOLUTION :`CH_3-undersetunderset(O)(\|\|)C-undersetunderset(Et)(\|)(CH)-Ph` If H, present on the chiral carbon, undergoes TAUTOMERISATION we will get racemic MIXTURE.