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In the previous problem find the loss of kinetic energy of the system during collision if the particles are moving unidirectionally. |
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Answer» Solution :`DELTA KE=(1)/(2)(m_(1)m_(2))/(m_(1)+m_(2))v_(1)^(2)(1-e^(2))` If they are UNIDIRECTIONALLY, the velocity of approach has the magnitude of `|u_(1)-u_(2)|=|5-10|=5` m/sec. `RARR Delta K.E. =((1)/(2)xx3xx6)/(3+6)=(5)^(2){1-(1//2)^(2)}=75//4 J`. |
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