1.

In the previous problem, suppose that another force in addition to the electrical force acts on the particle so that when it is released from rest, it moves to the right. After it has moved 5 cm, the addition force has done 9xx10^(-5 J of work and the particle has 4.5xx10^(-5) J of kinetic energy. (a) What work was done by the electrical force ? (b) What is the magnitude of the electric field ? (c) What is the potential of the starting point with respect to the end point ?

Answer»


Answer :(a) `-4.5xx10^(-5) J`
(B) `3XX10^(5) N//C`
(c) `-1.5xx10^(-4) V`


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