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In the previous problem, the maximum horizontal distance will beA. `160sqrt(3)m`B. `140sqrt(3)m`C. `120sqrt(3)m`D. `100sqrt(3)m` |
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Answer» Correct Answer - a Horizontal range, `R=(u^(2)sin 2 theta)/g` `R=((56)^(2)sin 60^(@))/(9.8)` `=(56xx56xxsqrt3)/(9.8xx2)=160sqrt3m` |
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