1.

In the previous problem, the maximum horizontal distance will beA. `160sqrt(3)m`B. `140sqrt(3)m`C. `120sqrt(3)m`D. `100sqrt(3)m`

Answer» Correct Answer - a
Horizontal range, `R=(u^(2)sin 2 theta)/g`
`R=((56)^(2)sin 60^(@))/(9.8)`
`=(56xx56xxsqrt3)/(9.8xx2)=160sqrt3m`


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