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In the previous problem, the minimum speed with which the body must be thrown from the surface of the earth so as to reach a height of `R//4` isA. `sqrt((gR)/2)`B. `sqrt(gR)`C. `sqrt((gR)/5)`D. `sqrt((2gR)/5)` |
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Answer» Correct Answer - D By energy conservation `K_(1)+U_(1)=K_(2)+U_(2)` `1/2mv^(2)-mgR=0-4/5 mgR` `v=sqrt((2gR)/5)` |
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