1.

In the previous question,

Answer»

velocity of B, OBSERVED by F (relative to itself), is equal to `4.25 ms^(-1)`
velocity of B, observed by F (relative to itself), is equal to `6 ms^(-1)`
velocity of B, observed by F (relative to itself), is equal to `5.50 ms^(-1)`
velocity of B, observed by F (relative to itself), is equal to `4.50 ms^(-1)`

Solution :In the PREVIOUS question, velocity of fish, observed by the bird, will be equal to `dr_(1)//dt`. Therefore, DIFFERENTIATING Eq. (i),
we get
`(dr_(1))/(dt)=(dx)/(dt)+(1)/(mu)(dy)/(dt)=4.50ms^(-1)`
Hence, OPTION (d) is correct. Similarly, velocity of bird, as observed by the fish, will be equal to `(dr_(2))/(dt)`
`(dr_(2))/(dt)=(1)/(mu^('))(dx)/(dt)+(dy)/(dt)=6.0ms^(-1)`
Hence, option (b) is correct. .


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