1.

In the previous question, if the second car is overtaking at a relative speed of 15 ms^(-1), how fast will the image be moving ?

Answer»

`1.2ms^(-1)`
`0.4ms^(-1)`
`0.12ms^(-1)`
`0.016ms^(-1)`

Solution :Here `(du)/(dt) =15 MS^(-1), (DV)/(dt) = ?`
`(1)/(u) + (1)/(v) = (1)/(f) : (-1)/(u^(2))(du)/(dt) - (1)/(v^(2)) (dv)/(dt) = 0`
`THEREFORE (dv)/(dt)=(v^(2))/(u^(2))(du)/(dt)=((19.4)/(600))^(2)xx15`


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