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In the previous question let `V_(0)` be the volume of each container. All other details remain the same. The number of moles of gas in the container at temperature `2 T_(0)` will beA. `(p_(0)V_(0))/(2 RT_(0))`B. `(p_(0)V_(0))/(RT_(0))`C. `(2p_(0)V_(0))/(3 RT_(0))`D. `(p_(0)V_(0))/(3 RT_(0))` |
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Answer» Correct Answer - D `(pV_(0))/(R.2T_(0)) = (4p_(0)V_(0))/(3R.2T_(0)) = (2p_(0)V_(0))/(2RT_(0))` |
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