1.

In the previous question, maximum permissible error is resitivity and resistance measurement will be

Answer»

`2.14%`, `1.5%`
`1.5%`, `2.45%`
`2.41%`, `1.1%`
`2.45%`, `1.5%`

SOLUTION :`((DR)/(R))_(MAX)=(DELTAI)/(i)+(Deltav)/(v)=`
`(0.1)/(10.0)+(0.1)/(100.0)=1.1% ((dR)/(R))_(max)=2.41%`


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