1.

in the previous question, suppose the switch is again opened at t=0, then time constant of discharging circuit is:

Answer»

`(L)/(R_(1))`
`(L)/(R_(2))`
`(L)/(R_(1)+R_(2))`
`(L(R_(1)+R_(2)))/((R_(1)R_(2))`

Solution :When the sitch is OPENED the circuit looks like as shown. Now, the circuit discharges with resistances
`R_(1)` and `R_(2)` in series, so TIME constant is `(L)/(R_(1)+R_(2))`.


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