1.

In the previous question what will be the terminal potential difference for the cells, which are connected with forward polarity?

Answer»

`((n+1) NE-4)/(n)`
`(nE-4)/(n)`
`((n+1) E-3)/(n)`
`((n-1) nE+4)/(n)`

Solution :We can continue the calculation from the PREVIOUS question. Terminal potential difference when current leaves the positive terminal of the battery is GIVEN as follows:
`V= E-r = nE- ((nE-4)/(nr)) r= (n^(2)E- nE + 4)/(n)`
`= ((n-1) nE + 4)/(n)` Hence, option (d) is correct


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