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In the problem if k = 10 N/m, m=2kg, R=1m and A=2m. Find linear speed of the disc at mean position. A. `sqrt((40)/(3)) m//s`B. `sqrt(20) m//s`C. `sqrt((10)/(3)) m//s`D. `sqrt((50)/(3)) m//s`

Answer» Correct Answer - A
`1/(2)kAY^(2) = 1/2 mv^(2) (1+(k^(2))/(R^(2))) = 1/2mv^(2)(1+1/2) = 3/4 mv^(2)`
`v = sqrt((2kA^(2))/(3m)) = sqrt((2(10)(2)^(2))/(3(2))) = sqrt((40)/(3))ms^(-1)`


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