1.

In the Q.122 how much distance is covered by the particle in returning to the starting point?

Answer»

`(2r_(0))/(a)`
`(r_(0))/(a)`
`(r_(0))/(2a)`
`(r_(0))/(4a)`

Solution :
`r_(1)=r_(0)(1-axx(1)/(2a))(1)/(2a)=(r_(0))/(4a)`
Total distance `=r_(1)+r_(2)=(r_(0))/(4a)+(r_(0))/(4a)=(r_(0))/(2a)`


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