1.

In the Q. 122 what will be the velocity of the particle when it returns to the starting point?

Answer»

`vecr_(0)`
`-vecr_(0)`
`2vecr_(0)`
`-2vecr_(0)`

SOLUTION :`vecr=vecr_(0)t-vecr_(0)at^(2)`
`RARR VECV=(dvecr)/(dt)=vecr_(0)-vecr_(0)a2t`
Returning at `t=(1)/(a)`
`rArr vecv_(1//a)=vecr_(0)-2vecr_(0)axx(1)/(a)`
`rArr vecv=-vecr_(0)`


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